Question

expand the given problem(a/4-b/2+1)^2​

Answer 1

Answer:

Answer:(a/4)²-2(a/4×b/2)+(b/2)². (Using identity [a-b]²= a²-2ab+b²

Answer:(a/4)²-2(a/4×b/2)+(b/2)². (Using identity [a-b]²= a²-2ab+b²a/16²-ab/8+b/4²

Answer:(a/4)²-2(a/4×b/2)+(b/2)². (Using identity [a-b]²= a²-2ab+b²a/16²-ab/8+b/4²Hope this will help you

Answer:(a/4)²-2(a/4×b/2)+(b/2)². (Using identity [a-b]²= a²-2ab+b²a/16²-ab/8+b/4²Hope this will help youIf you like my answer please mark me as brainlist

Answer 2

$\sf \: As we know, \\ \\\rm(a+b+c)²=a²+b²+c²+2ab+2bc+2ca \\ \rm \: So, \\ \rm \: Here : \\ \rm a=\dfrac{a}{4} ,\rm b = \dfrac{b}{2} ,\rm c=\dfrac{1}{1}$

$\sf Now \: putting \: values,\\ \\ \rm\dfrac{a {}^{2} }{4 {}^{2} } + \rm{ \dfrac{b {}^{2} }{2 {}^{2} } + \rm \dfrac{1}{1} - 2×\dfrac{a}{4}×\dfrac{-b}{2} - 2×\dfrac{-b}{2} + 2 \times 1 + 1×\dfrac{a}{4}}$

Cancelling,

We get,

$\sf = \rm{ \dfrac{a {}^{2} }{16} + \dfrac{b {}^{2} }{4} + 1 - \dfrac{ab}{4} - b + \dfrac{a}{2} }$

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