Question

Expand the log ax×by/cz​

Answer 1

Here chain rule will be applied…

Consider (2x+1) = a

Now differentiate on both sides with respect to ‘a’, we get,

2dx/da = 1

So, dx/da = 1/2 …(Eqn. 1)

Now, put (2x+1)=a in the main equation, you’ll get

y= a^5

Differentiating on both sides with respect to ‘a’ we get,

dy/da= 5a^4 …(Eqn. 2)

Now divide (Eqn. 2) by (Eqn. 1), we get

(dy/da)/(dx/da) =5a^4/(1/2)

So, dy/dx= 10a^4

Resubstituting value of ‘a’, we get

dy/dx= 10(2x+1)^4