Question

expand the question​

Answer 1

Answer:

4a^2 -2b^2 +c^2 -4ab +2ac -2bc

Step-by-step explanation:

(2a -b+c)^2

(2a-b+c)(2a-b+c)

4a^2 -2ab +2ac -2ab -2b^2 -bc +2ac -bc+c^2

4a^2 -2b^2 +c^2 -4ab +2ac -2bc

Answer 2

Answer:

It is in the form of

$(a - b + c) {}^{2}$

so,

$(2a - b + c) {}^{2}$

$=(2a) { }^{2} + </em><em>b { }^{2}</em><em>+ c {}^{2} - 2(2a)b - 2bc - 2c(2a)$

[tex] =4a^2+b^2+c ^2-4ab-2bc-4ac.

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