Math, asked by kkkk65, 11 months ago

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Answered by waqarsd
0

 {(a + b  + c)}^{2}  =  {a}^{2}  +  {b}^{2}  +  {c}^{2}  + 2ab + 2bc + 2ca \\  \\ now \\  \\  {(a  + ( - 2b) + ( - 3c))}^{2}  =  {a}^{2}   + 4 {b}^{2}  + 9 {c}^{2}  - 4ab  +  12bc - 6ac \\   \\  \\  \\ \:  \:  \:   \:  \:  \:  \: \:  \:   \bold{ \large{hope \: it \: helps}}


kkkk65: in question there is - sign
kkkk65: ok mate
kkkk65: thanks
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