Question

expand the question of (101)cube

Answer 1

( 101 )³

=> ( 100 + 1 )³



We know, (a + b)³ = a³ + b³ + 3ab(a + b)


=> ( 100 )³ + ( 1 )³ + 3(100 × 1 )(100 + 1)


=> 1000000 + 1 + 300( 101 )


=> 1000000 + 30301


=> 1030301

Answer 2

Answer:

The expanded form of

$(100+1)^3=(100)^3+(1)^3+3(100)^2(1)+3(100)(1)^2=1030301$

Step-by-step explanation:

Given :

we are given a number

$(101)^3$

To Find :

Expand the above number using suitable identity

Solution :

Since we are given $(101)^3$

We know that 101 can be written as

$101=100+1$

Now the suitable identity

$(a+b)^3=a^3+b^3+3ab^2+3a^2b$

Substitute a =100 and b = 1 in the above identity

$(101)^3=(100+1)^3$

$(100+1)^3=(100)^3+(1)^3+3(100)^2(1)+3(100)(1)^2$

                $=1000000+1+3(10000)(1)+3(100)(1)$

                $=1000000+1+30000+300$

                $=1030301$

Hence we have concluded that the expanded form of

$(100+1)^3=(100)^3+(1)^3+3(100)^2(1)+3(100)(1)^2=1030301$

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