Question

Expand the question of (k+4)
=(k)^3+3×k^2×4+3×k×(4)^2+(4)^2
=k^2+12k^2+48k+64​ my answer is correct or not plz ans fast

Answer 1

Answer:

Step-by-step explanation:

Expand the question of (k+4)  ^3

We know that  

 (a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3

Now putting the values of a and b we get a = k and b = 4

(k + 4)^3 = k^3 + 3k^2 4 + 3k(4)^2 + 4^3

(k + 4)^3 = k^3 + 12 k^2 + 48 k + 64