Question

expand the using identity (2x_y+z)2​

Answer 1

♣ here is your answer mate:-

★ (a+b+c)²= a²+b²+c²+2ab+2bc+2ac..

(2x-y+z)²
=>(2x)²+(-y)²+(z)²+(2*2x*-y)+
(2*-y*z)+(2*2x*z).

=> 4x²+y²+z²-4xy-2yz-4xz...

♥ hope it will help you dude!!

Answer 2

$\bold{Question = >}$

$\bold{ ({2x - y + z})^{2}}$

$\bold{Answer = > }$

$\boxed{ {(a+ b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab+ 2bc + 2ca}$

$a = 2x \\ b = - y \\ c = z$

[substitute the values in the formula]

$\bold{ = {2x}^{2} + ( { - y}^{2}) + {z}^{2} + (2 \times 2x \times - y )+( 2 \times - y \times z) + (2 \times z \times 2x)}$

$\bold{= {2x}^{2} + {y}^{2} + {z}^{2} + ( - 4xy) + ( - 2yz) + 4xz}$

$\bold{ = {2x}^{2} + {y}^{2} + {z}^{2} - 4xy - 2yz + 4xz}$

$\bold{ = {2x}^{2} + {y}^{2} + {z}^{2} - 4xy - 2yz + 4xz}$