Question

expand this :-
unit- algebra
chapter- expansions​

Answer 1

Answer:

As per the formula of (a-b)^3

we get;

(3a)^3-(1/a)^3-3*3a*1/a(3a-1/a)

= 27a^3 - 1/a^3 - 9(3a-1/a)

= 27a^3 - 1/a^3 -27a + 9/a

Answer 2

Hope it's helpful to you.