Question

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Using the formula of-
(a-b)^3
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Answer 1

AnSwEr

${\tt{\red{\underline{\large{Given}}}}}$

• (x-y+2z)³

${\sf{\green{\underline{\large{To\:find}}}}}$

• break it into (a-b)³

${\sf{\pink{\underline{\Large{Explanation}}}}}$

we know that (a+b)³

(a+b)³=a³+b³+3ab(a+b)

Let x-y = a

Then

(a+2z)³ =a²+4z²+6az(a+2z)

¶utying the value of a in the Polynomial

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=>(a+2z)³ =a³+4z³+6az(a+2z)

=>(x-y+2z)² = (x-y)³+4z³+6(x-y)z(x-y+2z

=>(x-y+2z)² = x³-y³-3xy(x-y)+4z³+6(x-y)z(x-y+2z

=>(x-y+2z)² = x³-y³-3xy(x-y)+4z³+6zx-6yz(x-y+2z)

=>=>(x-y+2z)² = x³-y³-3xy(x-y)+4z³+6zx-6yz(x-y+2z)

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