Question

expand using cubic identity (p-2) (p+1) (p-4)​

Answer 1

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Suitable identities is (x+y)3=x3+3x2y+3xy2+y3

Here x=p and y=1

Therefore, value of (p+1)3 is

=(p)3+3(p)2(1)+3(p)(1)2+(1)3

=p3+3p2+3p+1