Question

expand using eeidentity [1/7u-1/3v+14]²​

Answer 1

Given: The expression [1/7u-1/3v+14]²​

To find: Expand using identity.

Solution:

(considering u and v are in denominator)

• Now we have given the expression as:

         [ 1 / 7u  -  1 / 3v  +  14 ]²

• Now we know the formula:

         (a - b + c)^2 = a^2 + b^2 + c^2 - 2ab - 2bc + 2ac

• So applying this, we get:

         ​ [1/7u - 1/3v + 14]² = (1/7u)^2 + (1/3v)^2 + (14)^2 - 2(1/7u)(1/3v) - 2(1/3v)(14) + 2(1/7u)(14)

• Now simplifying it, we get:

         ​ [1/7u - 1/3v + 14]² = 1/49u^2 + 1/9v^2 + 196 - 2/21uv - 28/3v + 4/u

Answer:

        So the expanded form of given expression is:

​           [1/7u - 1/3v + 14]² = 1/49u^2 + 1/9v^2 + 196 - 2/21uv - 28/3v + 4/u