Question

expand using identify
$(2x + 3y - {4z)}^{2}$
​

Answer 1

Answer:

$\huge\mathtt{{\colorbox{silver}{ANSWER~~~↴}}}$

We solve the given expression (2x+3y-4z)²

as shown below:

(2x+3y-4z) ²

=(2x)² +(3y)²-(4z)²+(2×2x×3y)+(2×3y×(-4z))+(2×(-4z)×2x)

∵(a+b+c)²=a² +b²+c²+2ab+2bc+2ca)

=4x²+9y ² - 16z²+12xy-24yz-16zx

Hence, (2x+3y+4z) =4x² +9y² -16z² +12xy-24yz-16zx.

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

Answer 2

$\huge\purple{\fbox{\tt{༆αɴѕωєя༆}}}$

We solve the given expression (2x+3y-4z)²

as shown below:

(2x+3y-4z) ²

=(2x)² +(3y)²-(4z)²+(2×2x×3y)+(2×3y×(-4z))+(2×(-4z)×2x)

∵(a+b+c)²=a² +b²+c²+2ab+2bc+2ca)

=4x²+9y ² - 16z²+12xy-24yz-16zx

Hence, (2x+3y+4z) =4x² +9y² -16z² +12xy-24yz-16zx.