Question

expand using identites (3x+4y)^2​

Answer 1

Answer:

${(3x + 4y)}^{2} \\ = > ({3x})^{2} + ({4y})^{2} + 2 \times 3x \times 4y \\ = > 9 {x}^{2} + 1 6{y}^{2} + 24xy$

this is your answer ❤️