Question

Expand using identities (2x +4y) whole square

Answer 1

Answer:

$( {2x + 4y)}^{2}$

$it \: is \: in \: the \: form \: of \\ {a}^{2} + 2ab + {b}^{2}$

$({2x)}^{2} + 2(2x)(4y) + {(4y)}^{2}$

$4 {x}^{2} + 16xy + 16 {y}^{2}$

further if u want then divide by 4

${x}^{2} + 4xy + 4 {y}^{2}$

Answer 2

Given : (2x+4y)²

To find : Expansion using identities.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to expand the given algebraic expression using indentities)

Here, we will be using general algebraic identities.

So,

= (2x+4y)²

= [(2x)² + (2 × 2x × 4y) + (4y)²]

= 4x²+16xy+16y²

(This cannot be further expanded by using identities. That's why, this will be considered as the final result.)

Used identity :

• (a+b)² = a²+2ab+b²

Hence, the answer to the expansion is, 4x²+16xy+16y²