expand using identities (3x+2y)^3
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FORMULA=(a+b)^3
=a^3+b^3+3ab(a+b)
Now substitute,
a=3x
b=2y
=(3x)^3+(2y)^3+3(6xy)(3x+2y)
=27x^3+8y^3+18xy(3x+2y)
=27x^3+8y^3+18xy(3x)+18xy(2y)
=27x^3+8y^3+54x^2y+36xy^2
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