Expand using identity(2a+5b) 2
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Answer:
We need to find value of (−2a+5b−3c)
2
Suitable identity is (x+y+z)
2
=x
2
+y
2
+z
2
+2xy+2yz+2xz
Here x=−2a,y=5b and z=−3c
Therefore, the value of (−2a+5b−3c)
2
is
=(−2a)
2
+(5b)
2
+(−3c)
2
+2(−2a)(5b+2(5b)(−3c+2(−2a)(−3c)
=4a
2
+25b
2
+9c
2
−20a−30b+12ac
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