Question

Expand using identity(2p+3q+r)2

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Answer 1

Answer:

(2p+3q+r)² = ((2p+3q) + r)² =(2p+3q)² + r² + 2*r*(2p+3q)

                                           =4p² + 9q² + 12pq + r² + 4pr + 6qr

Step-by-step explanation:

Answer 2

The correct answer is 4p² + 9q² + 12pq + r² + 4pr + 6qr.

Given: The equation = $(2p+3q+r)^{2}$.

To Find: Expand the equation using identity.

Solution:

As we know,

$(a+b+c)^{2} =a^{2} +b^{2} +c^{2} +2ab+2bc+2ac$

Here, in this equation.

a = 2p, b = 3q and c = r.

(2p+3q+r)² = ((2p) + (3q) + r)²

= $(2p)^{2}$ +(3q)² + r² + 2(2p)(3q) + 2(3q)r + 2(2p)r

= 4p² + 9q² + 12pq + r² + 4pr + 6qr

Hence, the expansion of $(2p+3q+r)^{2}$ is 4p² + 9q² + 12pq + r² + 4pr + 6qr.

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