expand using identity (2x -3y+z)^3
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(2x-3y+2)^3
2x*3-3y*3+2*3
=6x-9y+6
And the star is for apply multiple
2x*3-3y*3+2*3
=6x-9y+6
And the star is for apply multiple
Answered by
0
(2x)^3+(-3y)^3+(z)^3+3(2x)(-3y)(z)
8x^3-27y^3+z^3+6x-9y+3z
i think this is right
8x^3-27y^3+z^3+6x-9y+3z
i think this is right
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