Question

expand using identity 3 x minus 2 Y + Z whole square​

Answer 1

This is your answer Mate

Hope it helps you ...

Answer 2

$(3x-2y+z)^2=9x^2+4y^2+z^2-12xy-4yz+6xz$

Step-by-step explanation:

Algebraic identity:

$(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2xz$

The given expression is

$(3x-2y+z)^2$

It can be rewritten as

$(3x+(-2y)+z)^2$

Using the algebraic identity we get

$(3x+(-2y)+z)^2=(3x)^2+(-2y)^2+z^2+2(3x)(-2y)+2(-2y)z+2(3x)z$

$(3x-2y+z)^2=9x^2+4y^2+z^2-12xy-4yz+6xz$

#Learn more

Expand using proper identities bracket 4 x minus 5 y z bracket whole square/

https://brainly.in/question/6589138