Question

expand using identity
$(2x + 3y - 4z) ^{2}$

Answer 1

Formula: (a-b-c)2 =a2+b2+c2-2ab-2ac+2bc

Given Values, a = 2x b = -3y c = -4z
Substitute the given values in the formula,
= (2x)2 + (-3y)2 + (-4z)2 - 2((2x)(-3y)) - 2((2x)(-4z)) + 2((-3y)(-4z))

= 4x2 + 9y2 + 16z2 + 12xy + 16xz + 24yz


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Answer 2

Hi friend
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Your answer
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EXPANSION
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using identity => (a + b + c)² = a² + b² + c² + 2(ab + bc + ca)

(2x + 3y - 4z)²

=> (2x)² + (3y)² + ( - 4z)² + 2[ (2x).(3y) + (3y).(- 4z) + (- 4z).(2x)]

=> 4x² + 9y² + 16z² + 2(6xy - 12yz - 8zx)

=> 4x² + 9y² + 16z² + 12xy - 24yz - 16zx

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