Question

expand using identity (x-1/2y+1/4z)^2​

Answer 1

${(x - \frac{1}{2y} + \frac{1}{4z} )}^{2} \\ \\ {(x)}^{2} + {( - \frac{1}{2y} )}^{2} + {( \frac{1}{4z} )}^{2} + 2[(x)( - \frac{1}{2y} ) + ( - \frac{1}{2y} )( \frac{1}{4z} ) + ( \frac{1}{4z} )(x)] \\ \\ {x}^{2} + \frac{1}{ {4y}^{2} } + \frac{1}{ {16z}^{2} } + 2[( - \frac{x}{2y}) + ( - \frac{1}{8yz} ) + \frac{x}{4z} ] \\ \\ {x}^{2} + \frac{1}{ {4y}^{2} } + \frac{1}{ {16z}^{2} } - \frac{x}{z} - \frac{1}{4yz} + \frac{x}{2z}$