Question

expand using identity :( x+2p2)2​

Answer 1

Expand using suitable identity:

(x−

3

2

y)

3

EASY

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ANSWER

We need to expand (x−

3

2

y)

3

Suitable identities is (x−y)

3

=x

3

−3x

2

y+3xy

2

−y

3

The value of (x−

3

2

y)

3

is

= (x)

3

−3(x)

2

(

3

2

y)+3(x)(

3

2

y)

2

−(

3

2

y)

3

= x

3

−2x

2

y+

3

4

xy

2

−

27

8

y

3