Expand using identity
(x + ⅘ y)3
please answer with steps ......
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1
Answer:
We need to expand (x−
3
2
y)
3
Suitable identities is (x−y)
3
=x
3
−3x
2
y+3xy
2
−y
3
The value of (x−
3
2
y)
3
is
= (x)
3
−3(x)
2
(
3
2
y)+3(x)(
3
2
y)
2
−(
3
2
y)
3
= x
3
−2x
2
y+
3
4
xy
2
−
27
8
y
3
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