Math, asked by rakshitakademani, 2 months ago

Expand using suitable identities
a) (2x+3y-z)²
b) (3a+2b)³​

Answers

Answered by mansilodwal
0

Answer:

(2x+3y-z)² = (2x)²+ (3y)² + (z)² + 2(2x)(3y) + 2(3y)(z) + 2(z)(2x)

= 4x² + 9y² + z² + 12xy + 6yz + 4zx

(3a+2b)² = (3a)² + (2b)² + 2(3a)(2b)

= 3a² + 4b² + 12ab

I hope it helps

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