Question

Expand using suitable identities (x+2y+4z)2 ​

Answer 1

(x + 2y + 4z)²

Using identity,

(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

Here, a = x, b = 2y and c = 4z

(x + 2y + 4z)²

= x² + (2y)² + (4z)²² + (2×x×2y) + (2×2y×4z) + (2×4z×x)

                   

= x² + 4y² + 16z²+ 4xy + 16yz + 8xz

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