Question

Expand using suitable identity (2a+3b+4c)^

Answer 1

Answer:

4a^2 + 9b^2 + 16c^2 + 12ab + 24bc + 16ca.

Step-by-step explanation:

This is of the form (a + b + c)^2.

(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca.

Here,

a = 2a

b = 3b

c = 4c.

(2a + 3b + 4c)^2 = (2a)^2 + (3b)^2 + (4c)^2 + 2(2a)(3b) + 2(3b)(4c) + 2(4c)(2a).

= 4a^2 + 9b^2 + 16c^2 + 12ab + 24bc + 16ca.

Hope this helps!!!!

Answer 2

Answer:

4a^2 + 9b^2 + 16c^2 + 12ab + 24bc + 16ca.

Step-by-step explanation:

This is of the form (a + b + c)^2.

(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca.

Here,

a = 2a

b = 3b

c = 4c.

(2a + 3b + 4c)^2 = (2a)^2 + (3b)^2 + (4c)^2 + 2(2a)(3b) + 2(3b)(4c) + 2(4c)(2a).

= 4a^2 + 9b^2 + 16c^2 + 12ab + 24bc + 16ca.

Hope this helps!!!!