expand using suitable identity(2x+ 1)^3
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Answer:
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(2x+1)³
Solution:-
=>8x³+12x²+6x+1
step by step explanation:-
We use Pascal's triangle for cofficient
=>(a+b)² ____1
__________1,2,1
=>(a+b)³___1,3,3,1
So, we need 1,3,3,1
the power of the term will sum to 3.
And the starting first then will be 3 and descend in 1s.
=>(2x+1)³ =>1(2x)³+3(2x)²(2)+3(2x)(1)+1×1³
=>(2x+1)³=>8x³+12x²+6x+1
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