expand using suitable identity (2x+3y+4z)²
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Answered by
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Answer:
Identity used: (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
Step-by-step explanation:
Answer: (2x)² + (3y)² + (4z)² + (2 * 2x * 3y) + (2 * 3y * 4z) + (2 * 2x * 4z)
= 4x² + 9y² + 16z² + 12xy + 24yz + 16xz
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- Answer:
- Answer:using identity:- (a+b+c)²=a²+b²+c²+2ab+2bc+2ca
- Answer:using identity:- (a+b+c)²=a²+b²+c²+2ab+2bc+2caStep-by-step explanation:
- Answer:using identity:- (a+b+c)²=a²+b²+c²+2ab+2bc+2caStep-by-step explanation:(2x+3y+4z)²= (2x)²+(3y)²+(4z)²+2(2x)(3y)+2(3y)(4z)+2(4z)(2x)
- Answer:using identity:- (a+b+c)²=a²+b²+c²+2ab+2bc+2caStep-by-step explanation:(2x+3y+4z)²= (2x)²+(3y)²+(4z)²+2(2x)(3y)+2(3y)(4z)+2(4z)(2x)(2x+3y+4z)²=4x²+9y²+16z²+12xy+24yz+16zx
- Answer:using identity:- (a+b+c)²=a²+b²+c²+2ab+2bc+2caStep-by-step explanation:(2x+3y+4z)²= (2x)²+(3y)²+(4z)²+2(2x)(3y)+2(3y)(4z)+2(4z)(2x)(2x+3y+4z)²=4x²+9y²+16z²+12xy+24yz+16zxthank u for giving me a chance ☺️
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