Expand using suitable identity (2x-3y+z)^2
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Answer:
(2x-3y+z)^2 = 4x^2 + 9y^2 + z^2 - 12xy - 6yz + 4xz
Step-by-step explanation:
(a-b+c)^2 = a^2 + b^2 + c^2 - 2ab -2bc+ 2ac
(2x-3y+z)^2 = (2x)^2 + (3y)^2 + (z)^2 - (2×2x×3y) - (2×3y×z) + (2×2x×z)
(2x-3y+z)^2 = 4x^2 + 9y^2 + z^2 - 12xy - 6yz + 4xz
Or you can take thia formula (a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc+ 2ac
And use negative value of -3y
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