Expand using suitable identity
(-2x+5y-3z)sq
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Answered by
175
Heya dear user !!!
Here is your answer,
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We know that
(a+b+c)² = a² + b² + c² + 2(ab + bc + ca)
So,
(-2x + 5y - 3z)²
= (-2x)² + (5y)² + (-3z)² + 2 [ (-2x)*5y + 5y*(-3z) + (-3z)*(-2x) ]
= 4x² + 25y² + 9z² + 2 [ (-10xy) + (-15yz) + 6xz ]
= 4x² + 25y² + 9z² - 20xy - 30yz + 12xz
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Hope it helps.
Here is your answer,
==================================
We know that
(a+b+c)² = a² + b² + c² + 2(ab + bc + ca)
So,
(-2x + 5y - 3z)²
= (-2x)² + (5y)² + (-3z)² + 2 [ (-2x)*5y + 5y*(-3z) + (-3z)*(-2x) ]
= 4x² + 25y² + 9z² + 2 [ (-10xy) + (-15yz) + 6xz ]
= 4x² + 25y² + 9z² - 20xy - 30yz + 12xz
==================================
Hope it helps.
Anonymous:
good answer..
Answered by
44
Answer:
Hope This Will Help
It is right Answer
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