Question

expand using suitable identity (2x-y-z)^2

Answer 1

Answer:

${(2x - y - z)}^{2} \\ = {(2x)}^{2} + {(y)}^{2} + {(z)}^{2} - 2 \times 2x \times y + 2 \times y \times z - 2 \times 2x \times z \\ 4 { x}^{2} + {y}^{2} + {z }^{2} - 4xy + 2yz - 2zx$

hope it will help you