Expand using suitable identity (3a+4b)^3
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Answered by
8
Answer :-
• indentity used :- (a + b)³ = a³ + b³ + 3a²b + 3ab²
=> (3a + 4b)³
=> (3a)³ + (4b)³ + 3.(3a)².4b + 3.3a.(4b)²
=> 27a³ + 64b³ + 108a²b + 144ab²
Answered by
3
Answer:
(3a+4b)² = (3a)²+(4b)²+2×3a×4b
= 9a²+16b²+24ab
using identity
(a+b)²= a²+b²+2ab
hope it will help you
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