Question

Expand using suitable identity (3a+4b)^3​

Answer 1

Answer :-

• indentity used :- (a + b)³ = a³ + b³ + 3a²b + 3ab²

=> (3a + 4b)³

=> (3a)³ + (4b)³ + 3.(3a)².4b + 3.3a.(4b)²

=> 27a³ + 64b³ + 108a²b + 144ab²

Answer 2

Answer:

(3a+4b)² = (3a)²+(4b)²+2×3a×4b

= 9a²+16b²+24ab

using identity

(a+b)²= a²+b²+2ab

hope it will help you