Question

expand using suitable identity(3a+5b-c)^2

Answer 1

9a²+25b²+c²+30ab-6ac-10bc

Step-by-step explanation:

formula:- a²+b²+c²+2ab+2bc+2ca

=(3a)²+(5b)²+(-c)²+2×3a×5b+2×5b×(-c)

=9a²+25b²+c²+30ab-6ac-10bc

here's ur answer mate

HOPE IT HELPS

Answer 2

Step-by-step explanation:

GIVEN : (3a+5b-c)² =?

by using identity .ie,. (a+b+c)²= a²+b²+c²+2ab+2bc+2ac

putting the given values of a=38. , b=5b. c=(-c)

: ==>( 3a+5b-c)²= (3a)² +(5b)²+ (-c)²+ 2*3a*5b + 2*5b*(-c) + 2*(-c)*3a

==> 9a²+25b²-c²+30ab -10bc -6ac

so we get ,

(3a+5b-c)²= 9a²+25b²-c²+30ab-10bc-6ac

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