Question

Expand using suitable identity (3b+2a)^3

Answer 1

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Answer 2

Step-by-step explanation:

We need to expand (2a−3b) 3

We know suitable identity is (x−y) 3

=x 3 −3x 2 y+3xy 2 +y 3

Here x=2a and y=3b

Therefore, value of (2a−3b) 3 is

=(2a) 3 −3(2a) 2(3b)+3(2a)(3b) 2 −(3b) 3

=8a 3−36a 2 b+54ab 2−27b 3

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