expand using suitable identity
a) (3-5x) (3+5x)
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) (5x – 3) (5x + 3) = (5x)2 – (3)2 (Using identity 3) = 25x2 – 9 (ii) 103 x 99 (100 + 3) x (100 – 1) (100 + 3) x {100 + (- 1)} = (100)2 + {3 + (-1)} 100 + (3) (-1) (Using given identity) = 1000 + 200 – 3 = 10197Read more on Sarthaks.com - https://www.sarthaks.com/820274/find-the-product-using-suitable-identity-i-5x-3-5x-3-ii-103-x-99?show=820277#a820277
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