Expand using suitable identity: (a2 + 2b + 3ac)2
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Using the identity is (x−y)
2
=x
2
+y
2
−2xy.
Given: (3a−2b)
2
we apply the above identity by taking
x=3a and y=−2b
We get, (3a−2b)
2
=(3a)
2
+(2b)
2
−(2×3a×2b)=9a
2
+4b
2
−12ab
Hence, (3a−2b)
2
=9a
2
−12ab+4b
2
.
Step-by-step explanation:
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