Question

Expand using suitable identity ( pq-2r) (pq+2r)​

Answer 1

:

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$(p + q + (2r) {}^{2} = p {}^{2} + {q}^{2} (2 {r}^{2} )$

$+ (2 \times p \times q) + (2 \times q - 2 {r}^{2} ) +$

$(2 \times - 2r \times p) = {p}^{2} + {q}^{2} + 4 {r}^{2} + 2pq - 4pr - 4rp$

Hence=

$(2 - q - {r}^{2} = {p}^{2} +{q}^{2} + 4 {r}^{2} + 2pq - 4pq - 4rp$

Answer 2

Answer:

$( p + q = (2r)² = p² + q² (2r²)$

$+ (2×p×q) = ( 2 × q - 2r²) +$

$( 2 × -2r × p) = p² + q² + 4r² + 2pq - 4pr - 4rp$

$HENCE = (2 - q - r²  = p² + q² + 4r² + 2pq - 4pq -4rp )$

 Step-by-step explanation: