Math, asked by jaydevkumar, 1 year ago

expand using suitable identity (x+2y+3z)²

Answers

Answered by Thatsomeone
88
( x + 2y + 3z )^2 = ( x )^2 + ( 2y )^2 + ( 3z )^2 + 2 ( x )( 2y ) + 2 ( 2y ) ( 3z ) + 2 ( x )(3z)

= x^2 + y^2 + z^2 + 4xy + 12yz + 6xz

using identity

( a + b + c )^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ac

gyanabhi021: notcgood
gyanabhi021: not good
jaydevkumar: give full ans
Answered by jijyabraham21
6

Answer:

(x+2y+3z)^2

identity - a^2+b^2+c^2+2ab+2bc+2ac

      ans=  x^2+2y^2+3z^2+2x*2y+2*2y*3z+2x*3z

            = x^2+2y^2+3z^2+2x*2y+4y*3z+2x*3z

             = x^2+2y^2+3z^2+4xy+12yz+6zx

Step-by-step explanation:

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