expand using suitable identity (x+2y+3z)²
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( x + 2y + 3z )^2 = ( x )^2 + ( 2y )^2 + ( 3z )^2 + 2 ( x )( 2y ) + 2 ( 2y ) ( 3z ) + 2 ( x )(3z)
= x^2 + y^2 + z^2 + 4xy + 12yz + 6xz
using identity
( a + b + c )^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ac
= x^2 + y^2 + z^2 + 4xy + 12yz + 6xz
using identity
( a + b + c )^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ac
gyanabhi021:
notcgood
Answered by
6
Answer:
(x+2y+3z)^2
identity - a^2+b^2+c^2+2ab+2bc+2ac
ans= x^2+2y^2+3z^2+2x*2y+2*2y*3z+2x*3z
= x^2+2y^2+3z^2+2x*2y+4y*3z+2x*3z
= x^2+2y^2+3z^2+4xy+12yz+6zx
Step-by-step explanation:
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