expand (x+1)3 using an identity
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(x+1)^3=x^3+1^3 +3*x*1
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Hi !
(a+b) ³ = a³ + 3a²b + 3ab² + b³
a = x , b = 1
(x+1)³ = x³ + 3x² + 3x + 1
(a+b) ³ = a³ + 3a²b + 3ab² + b³
a = x , b = 1
(x+1)³ = x³ + 3x² + 3x + 1
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