Question

Expand( x + 1/x ) using binomial theorem....plz help to answer this question

Answer 1

yes it is message me now

Answer 2

(1+x)1/x=exp(1xln(1+x))=exp(1−x2+x23+O(x3))==exp(1)exp(−x2)exp(x23)exp(O(x3))==e(1−x2+x28)(1+x23)+O(x3)=e(1−x2+11x224+O(x3))(1+x)1/x=exp⁡(1xln⁡(1+x))=exp⁡(1−x2+x23+O(x3))==exp⁡(1)exp⁡(−x2)exp⁡(x23)exp⁡(O(x3))==e(1−x2+x28)(1+x23)+O(x3)=e(1−x2+11x224+O(x3))

from which

1x2((1+x)1/x−(1−x/2)e)==1x2⎛⎝⎜⎜⎜⎜e(1−x2+11x224)−(1−x/2)e+O(x3)⎞⎠⎟⎟⎟⎟==1124e+O(



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