expand (x-2)³ by using standard formulae
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Answer:
x³+6x²+12x+8.
Step-by-step explanation: We know that (a+b)³ = a³+b³+3ab(a+b). [x+2]³ = x³+2³+3(x)(2)(x+2). [x+2]³ = x³+8+6x(x+2).
Answered by
1
Your Answer:
The standard Formula of finding the cube of sum of two variables is
(x+y)³=x³+y³+3xy(x+y)
So,
(x+2)³
=x³ + 2³ + 3(x)(2)(x+2)
=x³ + 8 + 6x(x+2)
=x³ + 8 + 6x² +12x
=x³ + 6x² + 12x + 8
So, the expanded form of (x+2)³ is x³+6x²+12x+8
Additional:
The another Formula two find the cube of sum of two variable is
(x+y)³=x³+y³+3x²y+3xy²
Some, other formulas are
- (x+y)²=x²+y²+2xy
- (x-y)²= x²+y²-2xy
- (x+a)(x+b)= x²+(a+b)x+ab
- x³+y³=(x+y)(x²+y²-xy)
- x³-y³=(x-y)(x²+y²+xy)
Concept used:-
Multiplication of numbers
Addition of Numbers
Cubing of Number
Opening of Brackets
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