Expand (x/2-3/x)3
Please give answer and explanation on how to do it. The three at the end is the cube
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Step-by-step explanation:
solving it by the formula (a-b)^3
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Step-by-step explanation:
(a - b)^3 = a^3 + 3ab(b-a) - b^3
(x/2 - 3/x)^3 =
(x/2)^3 + 3(x/2)(3/x)[3/x - x/2] - (3/x)^3
= (x^3)/8 + (9/2)[(3x - x^2)/2x] - 27/(x^3)
= (x^3)/8 + (9/2)[(3 - x)/2] - 27/(x^3)
= (x^3)/8 + [(27-9x)/4] - 27/(x^3)
= {4(x^6) + 8(x^3)[27 - 9x] - 864}
If you can try to factorise this equation then it's fine. I don't know how to factorise this but I tried for so much time.
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