Math, asked by joshua24, 6 months ago

Expand (x^2+3/x)^3 using the binomial theorem​

Answers

Answered by kritigaindhar41
4

Step-by-step explanation:

(x^2+3/x)^3

[(a+b)^3=a^3+b^3+3ab(a+b)]

(x^2)^3+(3/x)^3+(3*x^2*3/x)(x^2+3/x)

x^6+27/x^3+9x(x^2+3/x)

x^6+27/x^3+9x^3+27. ANSWER.

Hope it helped.

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