Expand (x^2+3/x)^3 using the binomial theorem
Answers
Answered by
4
Step-by-step explanation:
(x^2+3/x)^3
[(a+b)^3=a^3+b^3+3ab(a+b)]
(x^2)^3+(3/x)^3+(3*x^2*3/x)(x^2+3/x)
x^6+27/x^3+9x(x^2+3/x)
x^6+27/x^3+9x^3+27. ANSWER.
Hope it helped.
Similar questions