Math, asked by siddiquiz9734, 7 months ago

Expand (x-2/3y)^3 using suitable identity

Answers

Answered by SiddheshA208

2

Answer:

=(x-2/3y)^3

=x^3-8/27y^3-3(x)^2(2/3y)+3(x)(2/3y)^2

=x^3-8/27y^3-2x^2y+4/3xy^2

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