Question

Expand (x+2)^6 using binomial theorem

don't spam will report​

Answer 1

Step-by-step explanation:

We have,

$\tt{ \blue{(x + 2)^{6} }}$

$\sf{ = \:^{6}C_{0}( {x}^{6} ) + \:^{6}C_{1}( {x}^{5} ) \cdot 2 + \:^{6}C_{2}( {x}^{4} ) \cdot (2) ^{2} +\:^{6}C_{3}( {x}^{3} ) \cdot (2)^{3} + \:^{6}C_{4}( {x}^{2} ) \cdot (2)^{4} + \:^{6}C_{5}( x ) \cdot (2)^{5} + \:^{6}C_{6}(2)^{6} }$

$\sf{ = {x}^{6} + 6( {x}^{5} ) \cdot 2 + 15( {x}^{4} ) \cdot (2) ^{2} +20( {x}^{3} ) \cdot (2)^{3} + 15( {x}^{2} ) \cdot (2)^{4} + 6( x ) \cdot (2)^{5} + (2)^{6} }$

$\sf{ = {x}^{6} + 12{x}^{5} + 60{x}^{4} +160 {x}^{3} + 240 {x}^{2} + 192 x + 128 }$