Expand (x -2y/3y)^3 using a suitable identity.
Answers
Answered by
0
Answer:
(x - 2y/3y)³
=(x-2/3)³
By identity (a-b)³=a³-b³-3ab(a-b)
= x³ - (2/3)³ - 3(x)(2/3)[x-2/3]
= x³-8/27 - 2x(x-2/3)
= x³ - 8/27 - 2x² + 4/3
Answered by
0
Answer:
we solve it by
(a-b)^3=a^3+b^3-3ab (a-b)
(x-2/3)^3=x^3+(2/3)^3-3×x×2/3 (x-2/3)
=x^3+8/27-2x^2+4x/3
Similar questions