Math, asked by MASS73, 1 year ago

Expand (x -2y/3y)^3 using a suitable identity.​

Answers

Answered by adityamahale2003
0

Answer:

(x - 2y/3y)³

=(x-2/3)³

By identity (a-b)³=a³-b³-3ab(a-b)

= x³ - (2/3)³ - 3(x)(2/3)[x-2/3]

= x³-8/27 - 2x(x-2/3)

= x³ - 8/27 - 2x² + 4/3

Answered by parul682
0

Answer:

we solve it by

(a-b)^3=a^3+b^3-3ab (a-b)

(x-2/3)^3=x^3+(2/3)^3-3×x×2/3 (x-2/3)

=x^3+8/27-2x^2+4x/3

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