Expand (x + 2y + 4 z)?
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We need to expand (x+2y+4z)²
We know appropriate identity (x+y+z)2=x²+y²+z²+2xy+2yz+2xz
Therefore, the value of (x+2y+4z)2 is
=x²+(2y)²+(4z)²+2(x)(2y)+2(2y)(4z)+2(x)(4z)
=x²+4y²+16z²+4xy+16yz+8xz
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