expand:-
( x+3 )^5................
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(x + 3)⁵
Using Pascal triangle:
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
(a + b)⁵ = (a⁵ + 5a⁴b + 10a³b² + 10a²b³ + 5ab⁴ + b⁵)
Therefore,
(x + 3)⁵
= (x⁵ + 5 . x⁴ . 3 + 10 . x³ . 3² + 10 . x² . 3³ + 5 . x . 3⁴ + 3⁵)
= x⁵ + 15x⁴ + 90x³ + 270x² + 405x + 243
Using Pascal triangle:
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
(a + b)⁵ = (a⁵ + 5a⁴b + 10a³b² + 10a²b³ + 5ab⁴ + b⁵)
Therefore,
(x + 3)⁵
= (x⁵ + 5 . x⁴ . 3 + 10 . x³ . 3² + 10 . x² . 3³ + 5 . x . 3⁴ + 3⁵)
= x⁵ + 15x⁴ + 90x³ + 270x² + 405x + 243
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