Math, asked by samikshashardul25, 3 months ago

expand x^3+7x^2+x-6 in power of (x-3)​

Answers

Answered by dverma040
0

Step-by-step explanation:

put x=3

x^3+7x^2+x-6

=

3 {}^{3}  + 7 \times 3 {}^{2}  + 3 - 6

 =  > 27 + 63  - 3

 =  > 90 - 3

 =  > 87

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