Question

Expand ( x-3)whole cube​

Answer 1

(x-3)^3

=x^3-9x^2+27x-3^3

=x^3=x^3-9x^2 +27x-27

Answer 2

HEY MATE LET ME HELP YOU WITH IT,

GIVEN : WE HAVE TO EXPAND (X-3)^3

SOLUTION

$(x-3)^{3} = (x-3)(x-3)(x-3)\\x-3(x-3)(x-3)\\(x^2 -2ab + b^2)(x-a) [from (x-y)^2=x^2 + 2xy + y^2]$

$x^3 + y^3 - 3 x^2 y+ 3xy^2$

:. substitutig values,we get,

$x^3 - 9x^2 + 27x-27$

HOPE YOU ARE HELPED MATE.